Optimal. Leaf size=142 \[ -\frac {B}{3 c x \sqrt {b x^2+c x^4}}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}+\frac {(2 b B-3 A c) \sqrt {b x^2+c x^4}}{2 b^2 c x^3}-\frac {(2 b B-3 A c) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{2 b^{5/2}} \]
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Rubi [A]
time = 0.06, antiderivative size = 142, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {1159, 2031,
2050, 2033, 212} \begin {gather*} -\frac {(2 b B-3 A c) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{2 b^{5/2}}+\frac {\sqrt {b x^2+c x^4} (2 b B-3 A c)}{2 b^2 c x^3}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}-\frac {B}{3 c x \sqrt {b x^2+c x^4}} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 1159
Rule 2031
Rule 2033
Rule 2050
Rubi steps
\begin {align*} \int \frac {A+B x^2}{\left (b x^2+c x^4\right )^{3/2}} \, dx &=-\frac {B}{3 c x \sqrt {b x^2+c x^4}}+\frac {(-2 b B+3 A c) \int \frac {1}{\left (b x^2+c x^4\right )^{3/2}} \, dx}{3 c}\\ &=-\frac {B}{3 c x \sqrt {b x^2+c x^4}}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}+\frac {(-2 b B+3 A c) \int \frac {1}{x^2 \sqrt {b x^2+c x^4}} \, dx}{b c}\\ &=-\frac {B}{3 c x \sqrt {b x^2+c x^4}}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}+\frac {(2 b B-3 A c) \sqrt {b x^2+c x^4}}{2 b^2 c x^3}+\frac {(2 b B-3 A c) \int \frac {1}{\sqrt {b x^2+c x^4}} \, dx}{2 b^2}\\ &=-\frac {B}{3 c x \sqrt {b x^2+c x^4}}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}+\frac {(2 b B-3 A c) \sqrt {b x^2+c x^4}}{2 b^2 c x^3}-\frac {(2 b B-3 A c) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {b x^2+c x^4}}\right )}{2 b^2}\\ &=-\frac {B}{3 c x \sqrt {b x^2+c x^4}}-\frac {2 b B-3 A c}{3 b c x \sqrt {b x^2+c x^4}}+\frac {(2 b B-3 A c) \sqrt {b x^2+c x^4}}{2 b^2 c x^3}-\frac {(2 b B-3 A c) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{2 b^{5/2}}\\ \end {align*}
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Mathematica [A]
time = 0.11, size = 96, normalized size = 0.68 \begin {gather*} \frac {\sqrt {b} \left (2 b B x^2-A \left (b+3 c x^2\right )\right )-(2 b B-3 A c) x^2 \sqrt {b+c x^2} \tanh ^{-1}\left (\frac {\sqrt {b+c x^2}}{\sqrt {b}}\right )}{2 b^{5/2} x \sqrt {x^2 \left (b+c x^2\right )}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.45, size = 130, normalized size = 0.92
method | result | size |
default | \(\frac {x \left (c \,x^{2}+b \right ) \left (3 A \sqrt {c \,x^{2}+b}\, \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) b c \,x^{2}-3 A \,b^{\frac {3}{2}} c \,x^{2}-2 B \sqrt {c \,x^{2}+b}\, \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) b^{2} x^{2}+2 B \,b^{\frac {5}{2}} x^{2}-A \,b^{\frac {5}{2}}\right )}{2 \left (x^{4} c +b \,x^{2}\right )^{\frac {3}{2}} b^{\frac {7}{2}}}\) | \(130\) |
risch | \(-\frac {A \left (c \,x^{2}+b \right )}{2 b^{2} x \sqrt {x^{2} \left (c \,x^{2}+b \right )}}+\frac {\left (-\frac {A c}{b^{2} \sqrt {c \,x^{2}+b}}+\frac {B}{b \sqrt {c \,x^{2}+b}}+\frac {3 \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) A c}{2 b^{\frac {5}{2}}}-\frac {\ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) B}{b^{\frac {3}{2}}}\right ) x \sqrt {c \,x^{2}+b}}{\sqrt {x^{2} \left (c \,x^{2}+b \right )}}\) | \(145\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.63, size = 260, normalized size = 1.83 \begin {gather*} \left [-\frac {{\left ({\left (2 \, B b c - 3 \, A c^{2}\right )} x^{5} + {\left (2 \, B b^{2} - 3 \, A b c\right )} x^{3}\right )} \sqrt {b} \log \left (-\frac {c x^{3} + 2 \, b x + 2 \, \sqrt {c x^{4} + b x^{2}} \sqrt {b}}{x^{3}}\right ) + 2 \, \sqrt {c x^{4} + b x^{2}} {\left (A b^{2} - {\left (2 \, B b^{2} - 3 \, A b c\right )} x^{2}\right )}}{4 \, {\left (b^{3} c x^{5} + b^{4} x^{3}\right )}}, \frac {{\left ({\left (2 \, B b c - 3 \, A c^{2}\right )} x^{5} + {\left (2 \, B b^{2} - 3 \, A b c\right )} x^{3}\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {c x^{4} + b x^{2}} \sqrt {-b}}{c x^{3} + b x}\right ) - \sqrt {c x^{4} + b x^{2}} {\left (A b^{2} - {\left (2 \, B b^{2} - 3 \, A b c\right )} x^{2}\right )}}{2 \, {\left (b^{3} c x^{5} + b^{4} x^{3}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {A + B x^{2}}{\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.64, size = 107, normalized size = 0.75 \begin {gather*} \frac {{\left (2 \, B b - 3 \, A c\right )} \arctan \left (\frac {\sqrt {c x^{2} + b}}{\sqrt {-b}}\right )}{2 \, \sqrt {-b} b^{2} \mathrm {sgn}\left (x\right )} + \frac {2 \, {\left (c x^{2} + b\right )} B b - 2 \, B b^{2} - 3 \, {\left (c x^{2} + b\right )} A c + 2 \, A b c}{2 \, {\left ({\left (c x^{2} + b\right )}^{\frac {3}{2}} - \sqrt {c x^{2} + b} b\right )} b^{2} \mathrm {sgn}\left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {B\,x^2+A}{{\left (c\,x^4+b\,x^2\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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